The chapter gave two ways to answer any kinematics question — boost everything, or compute an invariant. Thirty-eight problems are where the second stops being a preference and becomes the only practical route.
🎯 Why this matters
Three printed results in this chapter do not survive being redone. That is not a complaint about the book; it is why the solutions here are worked rather than quoted, and why any number you intend to rely on is worth recomputing.Chapter 1 was the toolbox. This page is where you find out whether you can use it: the book’s own summary, the two-body kinematics formulary it gives you before the problems, and all 38 problems with worked solutions.
What you were supposed to take away
The book’s summary, expanded into what each item actually means and where it was built:
| You should now have↕ | What that means in practice↕ | § |
|---|---|---|
| the Lorentz transformations from general properties of space-time | Derived from five structural axioms — homogeneity, isotropy, relativity, the group property, causality — with light entering only at the end to fix c. The point is that this constrains ALL interactions, not just electromagnetism. | 1.1 |
| mass, energy and momentum, their transformation properties, and the invariants | m² = E² − p² defines mass as the norm of a 4-vector; "relativistic mass" does not exist; the mass of a system is not the sum of its parts. | 1.2–1.5 |
| the L and CM frames | Fixed target versus collider, and the quadratic penalty that decides which machine gets built. | 1.4–1.5, 1.12 |
| SI and natural units | ħ = c = 1, and the ability to put the factors back. ħc = 197.3 MeV fm is the constant you will use most. | 1.6–1.7 |
| cross-section, luminosity, decay rates, branching ratios, phase space | σ is an effective area; Lσ is a rate; Γτ = ħ; the golden rule splits any rate into a matrix element and a phase-space volume. | 1.6–1.7 |
| the basic aspects of a scattering experiment | Scattering is a Fourier transform: resolution costs momentum transfer, which costs beam energy. Form factors, Rutherford, Mott. | 1.8 |
| the names of the particle types and of the four interactions | The census: quarks, leptons, gauge bosons, hadrons; and why gravity never appears again. | 1.9–1.10 |
| how charged particles and photons lose energy and are detected | Bethe–Bloch and its 1/β² rise, bremsstrahlung and X₀, critical energy, λ₀, showers. | 1.11 |
| the sources: cosmic rays, accelerators, colliders | p = 0.3BR sizes every machine ever built; phase stability and stochastic cooling are what make them work. | 1.12 |
| the basic detector types, tracking and calorimetry | Eleven instruments, each exploiting one of the energy-loss mechanisms above — and each dying, eventually, of rate. | 1.13a–d |
If any row reads as unfamiliar, the problems below will find it — the topic filter maps onto these rows.
The two-body toolkit
Before the problems the book works out, once and for all, every kinematic quantity of a generic two-body scattering in terms of the invariants. These are equations (P1.1)–(P1.15), and they are worth having at hand rather than re-deriving: most of the 38 problems are one substitution into one of them.
Everything rests on two facts from §1.4–1.5: , and are the same in every frame, and each of them can be written either from the initial state or from the final state.
Before the algebra, the picture the formulary is about — and the labelling the book uses without ever drawing it:
Draw this before starting any problem. The book’s solution to Problem 1.15 opens by saying so, and it is the single most useful habit in the chapter: nearly every sign error in relativistic kinematics is a mislabelled angle.
Read left to right for the CM energy of a fixed-target machine; read the arrow for the beam energy you need to reach a given s. Both directions get used constantly.
Every symbol, one at a time
Hover or tap a symbol above — it lights up in the equation and its meaning, units and type appear here.
| Eq.↕ | Result↕ | What it is for↕ |
|---|---|---|
| P1.2–P1.3 | E_b = (s + m_b² − m_a²)/2√s ; E_a = (s + m_a² − m_b²)/2√s | CM energies of the two incoming particles. Note they sum to √s, as they must. |
| P1.4 | p_a = p_b = √(E*² − m²) | The common CM momentum of the initial state — equal and opposite by definition of the frame. |
| P1.5–P1.7 | E_c = (s + m_c² − m_d²)/2√s ; E_d = (s + m_d² − m_c²)/2√s ; p_c = p_d | |
| P1.8 | t = m_c² + m_a² + 2p_a p_c cos θ_ac − 2E_a E_c = m_d² + m_b² + 2p_b p_d cos θ_bd − 2E_b E_d | The momentum transfer written two ways — through the a→c vertex or the b→d vertex. Both are the same invariant. |
| P1.9–P1.10 | cos θ_ac = (t − m_a² − m_c² + 2E_a E_c)/(2p_a p*_c) | The scattering angle, extracted from t. See the warning below about how P1.9 is printed. |
| P1.11–P1.12 | in L (p_b = 0): t = m_b² + m_d² − 2m_b E_d ⇒ E_d = (m_b² + m_d² − t)/2m_b | The recoil energy of the target from the momentum transfer alone. This is the elastic-scattering workhorse of §1.8. |
| P1.13 | E_c = m_b + E_a − E_d = (s + t − m_a² − m_d²)/2m_b | The scattered particle's lab energy. Used in Problem 1.17 to get the opening angle without a single Lorentz transformation. |
| P1.14–P1.15 | u = m_d² + m_a² + 2p_a p_d cos θ_ad − 2E_a E_d ; in L, u = m_b² + m_c² − 2m_b E_c | The third invariant, and its simple lab form. With P1.13 it gives s + t + u = Σm² immediately. |
Six of these are the same formula with the labels permuted — which is the point. <strong>Learn the pattern, not the fourteen equations.</strong> Every energy is (s ± m² ∓ m²)/2√s in the CM, or (something − t)/2m_b in the lab, and every momentum is √(E² − m²).
⚠️ Equation (P1.9) as printed
The book prints
with masses in the last term. Its neighbour (P1.10) has energies in the same slot, and so does the equation it is derived from. Solving (P1.8) for the cosine gives
so the printed should be . The two coincide only when both particles are at rest, which is exactly the case where the angle is undefined.
Nothing later depends on it — Problem 1.17’s solution uses the correct relation in the equivalent form — but the formula as printed will not reproduce that problem’s answer.
⚙️ Engineer’s bridge — why invariants beat transformations
Problem 1.17 is deliberately solved twice: once by boosting every 4-vector into the CM and back, and once by computing and and substituting. The second route is shorter, and the reason will be familiar.
A Lorentz transformation is a change of basis. Carrying a problem through one means tracking every component of every vector through a matrix multiply, and every component is an opportunity to drop a sign. The invariants are basis-independent scalars — the checksums of the problem. You compute them once, in whichever frame is easiest, and they are then valid everywhere.
It is the same instinct as working with a norm, a determinant or a trace instead of the matrix entries: if the answer you want is a scalar, find a scalar route to it. And when you do need both routes, they are a free cross-check — which is precisely how the book uses them here.
Where it breaks: an invariant route exists only when the answer is a scalar, and a great deal of what this book measures is not. Anything angular — the distribution of §5.7, a Dalitz plot, a forward–backward asymmetry — is frame-dependent by construction, so you must name the frame and do the transformation. The rule is therefore narrower than it sounds: prefer invariants for quantities, and expect to work in a specified frame the moment the question is about a direction.
Reproduce it
import numpy as np
mp = 0.93827209 # GeV
p1, th = 3.0, np.radians(10.0) # Problem 1.17
E1 = np.hypot(p1, mp)
s = (E1 + mp)**2 - p1**2
print(f"P1.1 check: s = {s:.4f} GeV^2 from (E_a+m_b)^2-p_a^2, "
f"and E_a back out = {(s - 2*mp**2)/(2*mp):.4f} GeV")
rs = np.sqrt(s)
Ecm = rs/2 # all four particles equal mass
pcm = np.sqrt(Ecm**2 - mp**2)
t = 2*pcm**2*(np.cos(th) - 1) # elastic, equal masses
bad = (t - 2*mp**2 + 2*mp*mp) /(2*pcm*pcm) # (P1.9) as printed
good = (t - 2*mp**2 + 2*Ecm*Ecm) /(2*pcm*pcm) # with energies
print(f"P1.9 as printed (masses) : cos theta* = {bad:+.4f} -> {np.degrees(np.arccos(bad)):.1f} deg")
print(f"P1.9 with energies (right) : cos theta* = {good:+.4f} -> "
f"{np.degrees(np.arccos(good)):.1f} deg <- the input angle")
u = 4*mp**2 - s - t # from the identity, then verify
print(f"s + t + u = {s+t+u:.4f} GeV^2 ; sum of m^2 = {4*mp**2:.4f} GeV^2"
f" -> identity holds") P1.1 check: s = 7.6593 GeV^2 from (E_a+m_b)^2-p_a^2, and E_a back out = 3.1433 GeV P1.9 as printed (masses) : cos theta* = -0.0152 -> 90.9 deg P1.9 with energies (right) : cos theta* = +0.9848 -> 10.0 deg <- the input angle s + t + u = 3.5214 GeV^2 ; sum of m^2 = 3.5214 GeV^2 -> identity holds
is not a formula to memorise, it is a constraint: it collapses three invariants to two. Fix and every possible event of this reaction lies somewhere on one straight line; the requirement that both and be negative cuts that line down to the coloured segment, whose two endpoints are forward and backward scattering. The elastic peak everyone measures sits at the crowded right-hand end — Problem 1.17’s 10° is already almost on top of the forward endpoint.
The problems
All 38, with a hint before the solution. The topic chips filter them; the progress bar and the “solved” ticks are stored in your browser.
📝 Chapter 1 problems
0/38 solved- Estimate the kinetic energy of a Boeing 747 at cruising speed and compare it with the energy released by a mosquito annihilating with an antimosquito.
- t
- km/h
- mosquito mass mg (assumed — the book leaves it to you)
- Three protons have momenta equal in magnitude and directions at from one another. What is the mass of the system?
- GeV each
- Compute the widths of the weak decays of the , and .
- ns
- ns
- ns
- Compute the lifetimes of the strongly decaying , , , , and from their total widths.
- MeV
- MeV
- MeV
- MeV
- keV
- MeV
- An accelerator produces a 20 GeV electron beam. Electrons scattered at are detected. Neglecting the recoil, what is the smallest structure in the proton that can be resolved?
- GeV
- In a collision the final state contains a particle of mass besides the two protons. (a) Give the threshold energy and momentum for a proton target at rest. (b) Give and for two protons colliding with equal and opposite velocities. (c) Evaluate both for a produced pion, and give the kinetic energy in case (a).
- Consider on a proton at rest. (a) Find the threshold photon energy. (b) The Universe is filled with 3 K background radiation of photon energy meV; find the minimum energy a cosmic-ray proton needs to induce photoproduction on it. (c) With mb just above threshold and a background photon density , find the attenuation length.
- The Universe is opaque to photons energetic enough that can occur on a background photon. Compute the threshold energy against (a) the 3 K microwave background at meV and (b) the extragalactic background light, taking m.
- The Bevatron was designed to have enough energy to produce antiprotons. What is the minimum proton beam energy? Baryon number conservation forces the reaction .
- At the LHC two proton beams of TeV collide head on. What beam energy would give the same centre-of-mass energy on a fixed hydrogen target? How does it compare with cosmic-ray energies?
- A particle of mass decays to two bodies of masses and . Give the energies and momenta of the products in the CM frame.
- Evaluate the CM energies and momenta of the products of and .
- Find the energies and momenta of the products of in the CM when .
- In a monochromatic beam of momentum some pions decay in flight as . We observe that in some cases the muons move backwards. Find the maximum for which this is possible.
- A of momentum GeV decays as . In the CM the proton makes an angle with the direction. Find (a) the CM energies and momenta, (b) the Lorentz parameters of the L–CM transformation, (c) the lab energy and momentum of the , and the lab angle and momentum of the .
- A ball collides elastically with an equal ball at rest. Compute the angle between the two final directions at non-relativistic speeds.
- A proton of momentum GeV scatters elastically on a proton at rest; one proton comes out at in the CM. Find (a) the kinematic quantities in the L frame, (b) those in the CM, (c) the angle between the final protons in L — is it ?
- A charmed meson decays as at mm from its production point. The total energy of the decay products is measured as GeV. How long did the live in proper time, and what is the momentum in the rest frame?
- mm
- GeV
- GeV
- A secondary monochromatic beam is produced at a target. At m from the target, 10 % of the pions have decayed. Find the momentum and energy of the pions.
- m
- 10 % decayed
- m
- A beam is stopped in liquid hydrogen, where are produced by charge exchange, . Find the energy of the , the kinetic energy of the neutron, the velocity of the and the distance it travels in one lifetime.
- A 2 GeV electron beam hits an iron target (take pure Fe). How large is the maximum four-momentum transfer?
- GeV
- GeV
- Geiger and Marsden found that alpha particles bounced backwards off a thin foil 'not too infrequently'. Calculate the ratio between the scattering probabilities for and for .
- A 6 MeV alpha beam of intensity crosses a m gold foil. Calculate the number of particles per unit time scattered at angles larger than 0.1 rad.
- ,
- m
- Electrons of 10 GeV are scattered by protons initially at rest, at . Find the maximum energy of the scattered electron.
- If GeV electrons scatter elastically and emerge with GeV, find the scattering angle.
- Find the ratio between the Mott and Rutherford cross-sections for the same particles at the same energy at .
- A particle of mass , charge C and momentum moves in a circular orbit at constant speed in a magnetic field normal to the orbit. Find the relation between , and .
- To measure the total cross-section at 20 GeV, a 1 m liquid-hydrogen target is placed between two scintillation counters. Normalised to the same incident flux, particles are counted with the target empty and with it full. Find the cross-section and its statistical error.
- m
- In the experiment of Chamberlain et al. in which the antiproton was discovered, the antiproton momentum was about GeV. What is the minimum refractive index needed to have the antiprotons above threshold in a Cherenkov counter? How wide is the Cherenkov angle if ?
- Two particles of masses and have the same momentum . Evaluate the difference in the times they take to cross a distance . With two scintillators measuring to 300 ps, how long must be to separate from at two standard deviations, if their momentum is 4 GeV?
- A Cherenkov counter containing nitrogen at pressure sits on a beam of momentum GeV. The index depends on the pressure as . The detector must see the and not the . In which range must the pressure be?
- Superman travels down an avenue at high speed. At a crossroads he sees the lights are green and continues, but is stopped by the police, who claim he crossed on red. Assuming both are right, what was Superman's speed?
- For the Cherenkov effect in water (), determine (1) the minimum velocity for radiating, (2) the minimum kinetic energy for a proton and for a pion, (3) the Cherenkov angle for a pion of energy MeV.
- A threshold Cherenkov counter contains N at a variable pressure, with (pascals). A beam of , and protons, all of the same momentum, crosses it. Knowing that the are above threshold for Pa, (a) find the momentum, (b) the minimum pressure at which the radiate, (c) the same for the protons.
- (1) What is the maximum energy of a cosmic-ray proton that remains confined in the Solar System ( m, nT)? (2) What is it for the Milky Way ( m, nT)?
- Portable neutron generators use He with deuterons accelerated to keV. (1) Calculate the neutron kinetic energy. (2) With an isotropic production rate , what is the neutron flux at m? (3) Tagging the neutron by detecting the , what time resolution is needed to locate a scattering nucleus to cm?
- , , , MeV
- Neutrons of a few MeV are to be detected in a TPC containing Ar. If the energy is low enough the nucleus scatters coherently, as a single object. Taking a nuclear radius fm, what is the minimum neutron kinetic energy needed to resolve the nuclear structure, and what is the maximum recoil energy of the nucleus at that limit?
- fm
- GeV
- Two photons of energies collide head on. If comes from a laser of wavelength nm, what is the minimum to produce an pair? Compute the CM velocity at threshold as . What is the mass of the two photons if they move in the same direction?
Further reading
The book’s own list for this chapter, which is unusually good — nine of the fifteen entries are Nobel lectures by the people who built the instruments:
- Wilson (1925), On the Cloud Method of Making Visible Ions and the Tracks of Ionising Particles — §1.13b
- Hess (1936), Unsolved Problems in Physics: Tasks for the Immediate Future in Cosmic Ray Studies — §1.12
- Blackett (1948), Cloud Chamber Researches in Nuclear Physics and Cosmic Radiation — §1.13b
- Glaser (1960), Elementary Particles and Bubble Chamber — §1.13b
- Alvarez (1968), Recent Developments in Particle Physics — §1.13b
- van der Meer (1984), Stochastic Cooling and the Accumulation of Antiprotons — §1.12
- Okun (1989), The concept of mass, Phys. Today June, 31 — the argument behind §1.4’s refusal to use “relativistic mass”
- Bonolis (2005), Bruno Touschek vs. machine builders: AdA, the first matter-antimatter collider — §1.12
- Grupen & Shwartz (2008), Particle Detectors, CUP, and Kleinknecht (1998), Detectors for Particle Radiation, CUP — the two standard references behind §1.13a–d
- Sci. Am. articles on the Tevatron (Lederman 1991), LEP (Meyers & Picasso 1990) and the SLC (Rees 1989)
Erratum — Eq. (P1.9) in the problem-section formulary
The CM scattering angle is printed as
It should carry energies, . Three independent checks agree:
- Its own neighbour. Eq. (P1.10), the same expression for the other pair, is printed with in exactly that slot.
- The equation it comes from. (P1.8) is ; solving it for the cosine returns , never a product of masses.
- Dimensions and limits. For massless particles the printed form would make depend on alone with no energy scale, which is wrong.
Feed Problem 1.17’s numbers through the printed version and it returns 91° for a configuration that had 10° put into it.
Erratum — two numbers in the book’s own Solutions section
The book solves some of these problems at the back (pp. 506–512). Two of its printed solutions do not survive being redone, so if you check your work against them, check these first. Both corrections are also in the solution notes of the problems above, where they belong; they are collected here because a reader comparing answers needs them before opening the problem, not after.
Solution 1.7(c), p. 506 prints the attenuation length as m Mpc, “(1 Mpc = m)”. Two things are wrong and they partly hide each other:
- With the problem’s own mb m² and m⁻³, m, not . To get the printed number you need mb.
- A megaparsec is m, not — the printed conversion is off by a factor of ten. It is what turns m into “18 Mpc”; the correct conversion of that same wrong length would be 1.8 Mpc.
Done consistently, the answer is m Mpc. The physics is unchanged — the GZK horizon is a few Mpc either way, which is the point of the problem — but a reader who trusts “1 Mpc = m” will carry a broken constant into every cosmological estimate afterwards. (The same solution also prints GeV² where it is 1.152, and hence MeV where it is 145.)
Solution 1.36(1), p. 510 prints MeV. The radicand is right and the root is not: MeV. 61.25 is what you get from MeV, and the problem says 130 keV. The conclusion — that the deuteron momentum is negligible, so the lab frame is the CM frame — is true either way, which is presumably why it survived proofreading.
The same solution writes and then correctly subtracts 3727.4, which is . The symbol is wrong, the arithmetic is right, and the printed 3.6 MeV is correct.
🔑 If you remember only three things
-
The formulary is the chapter, compressed. Nearly every problem reduces to s and t plus the two-body relations collected on this page — learn the shape of that list, not its entries.
-
Knowing a method is not the same as reaching for it. Everyone can recite that s is invariant; thirty-eight attempts is roughly what it takes before that becomes the first thing you write down.
-
Read the chapter’s own summary last, not first. “What you were supposed to take away” is a checklist, and a checklist is only useful to someone who has already tried and can tell which line they failed.
Where this goes next
Chapter 1 is finished. Chapter 2 stops building tools and starts using them: the discovery of the positron, the muon, the pion and the strange particles, all of it done with the cloud chambers, emulsions and counters of §1.13.
✅ Check yourself — the toolkit, before you use it
0/6 answered · 0 correct
1.Fourteen formulas P1.2–P1.15 look like a lot to memorise. What is the pattern that makes them one formula?
2.Problem 1.6 asks for the threshold to make a particle of mass m in pp collisions. Why is the collider answer E* = m_p + m/2 so much better than the fixed-target E_p = m_p + 2m + m²/2m_p?
3.Problem 1.16 gives exactly 90° between two equal balls after an elastic collision, but Problem 1.17 gives 86° for two protons at 3 GeV. What changed?
4.Problem 1.7 finds that a cosmic-ray proton above ~7×10¹⁹ eV can photoproduce a pion on a 1 meV microwave-background photon, with an attenuation length of a few Mpc. What does that imply?
5.Problem 1.20 finds a π⁰ from stopped-pion charge exchange travels 5.3 nm in a lifetime. What is the practical consequence?
6.Equation (P1.9) is printed with 2m_a m_c where the derivation requires 2E_a E_c. How would you have caught this without an external source?